Question
Let f(n)= 32n4+ 12 n log n . Then f(n)= O (?), f(n)= Q (?), f(n)= (?) Replace question marks with the correct answer
Let f(n)= 32n4+ 12 n log n . Then f(n)= O (?), f(n)= Q (?), f(n)= (?) Replace question marks with the correct answer (we look for the tightest bound once possible). Choose the correct case from the following options: None of the cases are correct. f(n)= O(n4), f(n)= Q(n log n), is not applicable f(n)= O(n4), f(n)= Q(n4), f(n)= 0(n) f(n)= O(n log n), f(n)= Q(n log n), f(n)= 0 (n log n) f(n)= O(n^), f(n)= Q(n), is not applicable f(n)= O(n), f(n)= Q(n), f(n)= O(n) Of(n)= O(log n), f(n)= Q(log n), f(n)= (log n)
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College Algebra
Authors: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
12th edition
134697022, 9780134313795 , 978-0134697024
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