Position vs. Time @0.0s d=0.0 cm@0.10s d=3.70cm@0.20s d=8.60cm@0.30s d=14.4cm@0.40s d=21.0cm@0.50s d=29.1cm@0.60s d=37.0cmVelocity vs. Time @0.10s v=42.50 cm/s@0.20s v=54.0 cm/s@0.30s v=64.5 cm/s@0.40s v=75.5 cm/s@0.50s v=84. 5 cm/s

Velocity. a. From your position-time graph - calculate the instantaneous velocity at 2 points - one near the beginning and one near the end of the time period. Recall instantaneous velocity is calculated on a curved line by calculating the slope of a tangent line. b. Explain how your answers show that the puck was accelerating. The puck is moving rightward but 20. 10 it's travelling Q + 93:75 um c. From your velocity vs. time graph - determine the velocity of the puck at those same and times. @ o. it's d. Compare your answers in a and c