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Pr bl m 3 Di saponifyesh n f di sta f nyl as tat ( E ) bay s dy m f n layt (

Prblm 3 Di saponifyeshn f di sta fnyl astat (E) bay sdym fnlayt (P.. DH09
)in akyu slushn g\epsi t di flw stoichiometry:
h
2.2.
1999.
O+CH we de na di wl
3.3.
1999.
COOC
6.6.
1999.
h
5.5.
1999.
+C
6.6.
1999.
h
5.5.
1999.
CH
3.3.
1999.
CO.O.
+2C
6.6.
1999.
h
5.5.
1999.
O
Shomed we dn mek
1999.
1999.
Dn dn tk bt dis we aw dn de du tin:
c
6.6.
1999.
h
5.5.
1999.
+H
2.2.
1999.
l
1.1.1.
1999.
TO
4.4.
1999.
1999.
1999.
c
6.6.
1999.
h
5.5.
1999.
OH+OH na wan
(rili fast)
O
+CH
3.3.
1999.
COOC
6.6.
1999.
h
5.5.
1999.
Yo
2.2.
1999.
1999.
CH
3.3.
1999.
COOH+C
6.6.
1999.
h
5.5.
1999.
CH
3.3.
1999.
COOH+OH we yu kin yuz
(tek tm)
->
1999.
Yo
3.3.
1999.
1999.
1999.
CH
3.3.
1999.
CO.O.
+H
2.2.
1999.
(rili fast)
1999.
(1)(2)(3)(a) If riakshn (2) na di stp we de stp di rit, us fm yu de kspkt di rt ikwshn f di vala riakshn f tek? ksprs yu ansa nm insay di spshal wan dn we de apia na di vala stoichiometrik ikwshn. Na ya wi mek E riprizent \epsi sta f\epsi nyl aset\epsi t, P
riprizent sdym f\epsi nolet, \epsi n P riprizent f\epsi nol. Assume di knsntreshn f wata na knstant.(b) Di kspirimnt data we de d ya gri wit dis mkanism? If na so, wetin na di r\epsi t knstant we d\epsi n obs\epsi v \epsi ksp\epsi ri\epsi ns? Notis se di initial konsantreshn d\epsi m f di \epsi sta \epsi n di f\epsi nolet ayn ikwal to wan an.

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