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PRACTICE ANOTHER An article summarizes results from a survey of 420 participants. The article reported that 71% of the 420 survey participants said that

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PRACTICE ANOTHER An article summarizes results from a survey of 420 participants. The article reported that 71% of the 420 survey participants said that they had made up an excuse not to attend an online meeting just because they didn't feel like attending (the most popular excuse was internet problems). If p = 0.71 is used as an estimate of the proportion of working adults who have made up an excuse not to attend an online meeting, is it likely that this estimate is within 0.05 of the actual population proportion? Use what you know about the sampling distribution of p to support your answer. (Round your answer to four decimal places.) We know the sampling distribution of p will be centered at the ---Select--- distribution is approximately normal . So, we can , and the standard deviation of this distribution can be estimated as . In addition, the sampling say our value of p is likely to be within 0.05 of the actual value because of the following fact. The Empirical Rule implies about 95% of our sampling distribution's values will fall within two standard deviations of the center, and two standard deviations is less than 0.05. The Empirical Rule implies about 95% of our sampling distribution's values will fall within two standard deviations of the center, but two standard deviations is greater than 0.05. The Empirical Rule implies about 95% of our sampling distribution's values will be at most one standard deviation away from the center, and our standard deviation is less than 0.05. We cannot make use of the Empirical Rule since our sampling distribution isn't mound shaped and symmetric. The Empirical Rule implies about 95% of our sampling distribution's values will be at most one standard deviation away from the center, but our standard deviation is greater than 0.05. Need Help? Read It

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