Pre Calc Practice Quiz

If a parabola's focus is at (3, 8) and directrix is at y = 2, what is the vertex form of the equation representing this parabola? Oy= 17(1 -3)2 +5 oy= 4(x-3)2+3 oy= 1(x+3)2 +8 Oy= -17(2+3)2 -5-2 y =2 -1 -1 --1 P( X, y ) +-2 -3 F ( 3, -4) in What is the equation of the parbola shown below, given the focus at F(3, -4) and the directrix y = 2? Identify the vertex and the equation of the axis of symmetry of the parabola. O y = 12(2 + 3)2 - 1; vertex (3, -1); axis of symmetry is = = 3 Oy= - 12(x - 3)2 - 1; vertex (3, -1); axis of symmetry is z = 3 Oy= -1(x -3)2 + 1; vertex (-3, 4); axis of symmetry is = = -3 oy= (x+ 4)2 +3; vertex (-3, 4); axis of symmetry is z = 2The equation of a quadratic relation is y = = (@ - 3) + 3. Every point on this conic is equidistant from the focal point (a, b) and the line defined by y = c. Determine the value of a + b + c. 0 9 O 10 O 7 0 8Find the centre and radius of the circle a' + y' + 6: -4y -23 = 0. O centre (3, 2), radius 6 O centre (-3, -2), radius 6 O centre (-3, 2), radius v 6 O centre (-3, 2), radius 6What is the equation of the circle with centre 1,0) and radius 47 O (2x - 1)2 +y = 16 2 O (2x - 1)2 - y = 16 4 O (2x - 1)2 + y' = 4 4 O (2x - 1)2 + y? = 16 4