Probability distribution of calls. let say it is f (t).

As the given function is a discrete uniform probability function.

so Here P(0) = P(1) = P(2) = P(3) = P(4) = P(5) = P(6) = 1/7

so here fewer than 3 calls are received per hour means we will receive either 0 ,1 or 2 calls

so P( fewer than 3 calls) = P(0) + P(1) + P(2) = 1/7+ 1/7 + 1/7 = 3/7 = 0.4285

How do you explain this in reference to the following problem?

Suppose that incoming calls per hour to a customer service center of a small credit union are uniformly distributed between 0 and 6 calls. What is the probability that fewer than 3 calls are received per hour? O O VIA oilw old w/w O O