Probability of B = 0.8961, Probability of C = 0.9571. (Info about B, mean = 0.03, n=85, had to calculate the probability that the mean falls between 0 - 0.06). (Info about C, mean = 0.03, n=85, had to calculate the probability that the mean falls between 0 - 0.06. Also had to simulate 10,000 sample proportions)

Part D: Explain why the probabilities calculated in Parts B and C are so different. Hint: Are the conditions met to use the normal approximation to the samplin: distribution of p in this case? Part D: Explain why the probabilities calculated in Parts B and C are so different. Hint: Are the conditions met to use the normal approximation to the samplin: distribution of p in this case