Problem #1 For the thin-walled section properties and geometry shown below: Section Centroid Information: x = 10' y=5 Section Second Moments of Area: 13at 11at at 1xx = 15yy ,lxy 20 10 Section Geometry: Yref A a 3 X 1 2t a y 17 2 a 2t S 4 Xref 1. Derive the shear flow distribution equation "q12" in terms of "s" assuming vertical shear load Sy applied through the section shear center. Detail your solution and simplify your final equation. Do not find the shear center location, there is no need for it 2. Evaluate 12 at s = a (15 pts) (5 pts)