Question
Problem 1 MWFRS Design Loads - Envelope Procedure (50 pts.) Using the procedure shown on Table 28.2-1, you are required to analyze a 256x148x20 warehouse
Problem 1 MWFRS Design Loads - Envelope Procedure (50 pts.) Using the procedure shown on Table 28.2-1, you are required to analyze a 256x148x20 warehouse building structure located in St. Louis, MO. Refer to the video archives and lecture notes from 11/16/21 and 11/18/21. We discussed in class the MWFRS analysis for the transverse wind. You are now required to reproduce in Excel the transverse analysis and determine the longitudinal analysis using this time Load Case B from Fig. 28.3-1. Pay close attention to Notes 7 and 8. Below is the building data. Building Data: 1. Size: 256 wide x 148ft long x 20ft eave height 2. Use: Commercial Warehouse 3. Location: St. Louis, MO 4. Topography: flat 5. Surface roughness C 6. Framing: steel open web truss girders with interior posts 7. Roof: gable type 8. Purlins: open web steel joist at 8ft on center running along the 37ft dimension 9. Screwed down metal deck over the roof joists. Metal deck plus in-plane bracing provides in-plane diaphragm action at roof level to transfer lateral loads to the MWFRSs. 10. Cladding: Prefabricated precast concrete panels 11. Lines of resistance: a. b. Required: Transverse lines 1-5 Longitudinal lines A-H 1. Show in a tabulated format (Excel) all design wind loads for P transverse and longitudinal directions. (+i) and P (-i) for both 2. Only provide hand calcs for the longitudinal direction. No need to rewrite the transverse calcs by hand. 3. Show the design wind forces ONLY for line C in lb/ft. Display design loads on the framer for P(+i) and P(-i). See the LFRS sketch provided on the last page of the lecture notes from 11/18. No need to use load combinations at this time.
116 63% 1 Note on Wind loads on Buildings: MWERS Envelope Procedure Chater 28 diaphragma All bldo's have LERS in both orthogonal directions LERS for long loads LFRS for W, EQ Transverse loads wws wsze 6 stei zoo.c. Ji@ 140.6. 6/4.. 4'00 IN 0 w Plan View -Truss girder with two interior columns 2 A secnion 1-1 KA X 3 4, Ib TA' 4, PEKA. K=F/A The roof panel/assembly acts in the plane of the wof. out of plane as a diaphragm Transverse loading Longitudinal In-plane loading TICHI shear wall si-in-plane deflection 4 EX Det. A WFk loads using Enrelope pwedure . who warehouse Purlin length = 37' Precast concrete wall panels Purlin spacing = 80. open websteel joist Joist girders = 37'0.c. Roof: gable structure one story building 256 x 140 x zo' Location is st. Louis, Mo slope /: 12 Roof surface roughness: C topography: flat X 20 146 Plan LRidge at purlin (Jolst) THE HE -25.4" 11 WW2 5 MacBook Air 5 1 6 63% + WEH 937loc Review Table 20.2-) step procedure Elon 8 32o.c. IC + + 1. Risi cate gory Table 1.5-1 Assign Category Basic wind speed y 26.5-1 and 26.5-2 wind hazard map secrion 26.5.113 V = 107 mph Table 26.60) wind load parameters Directionality Factor Kd = 0.85 MWFRS and C&C 2. a. 6 / 6 KED, Directionality factor Exp c 6 b. Exposure category Seeron 26.7 Flat Ilg 26.8-1 6. Topographic factor Kzt = 10 d. Ground elevation factor ke sl.o Table 26.94 e. enclosure classification section 26.12 Enclosed BloG - STWcture f. Internal pressure coefficient Gp Table 26.13-) Gepi- & 0.18 for enclosed blogs 4. Velocity pressure exposure coefficient Kz or Kn Exp c/ki one variable ht O-IS 0.85 20 0.90 25 0.94 1 / 6 1. (. 26.- = ? (44 2011- 20 15 - Top 5. Velocin pressure for the Eq 0.85, + 4 k, . 24 4 4 4 4% 02 2 . 24. 913 L2 25-4 He (0+ 25, 233) 22.62 2 Cave 2 he r 4 0.85 ghorpe 21. 22.42 . 4o 20 173.17] 22.67 0.93 0.4T 23.42 2S 6, 18, 3-) 6. External pressure coefficient GCp 2 NOTE Edge zones transverse direction TAT 26 w 3E 30 ZE TE Roof angle Building Surfaces Fig 23.3-1 (GCpf) 2 3 4 4 7:12 0=2386 0.4 0.69.0.37 -0.29 0.61 -1.07 -0.53 -0.43 the diree non is pressure are direction is suction 0.5x hor. dim. parallel to direction of MW FRS) smaller Note 8 & 2.5x EH 1.07 3 6 -0.69 3 and 2E GEpf ore in zones 3 1 6 61% + 4.07 -0.69 Gepf ore in zones 3 and 2E 0.5x256 = 12e' ' 2.5x22,6% = 56.7' controls AWS 2 3 4 Windward hard Pag [GCpt - GCR IPPS TABETZ ctos Roof Plan () psf) 57 Surface 23.17 2 2 Gepf 0.4 -0.69 -0.37 -0.29 Piti) .10 -20.16 -12.74 -10.89 13.44 -(1.82 -4.40 -2.55 4 9.96 1330 4 12.30 15 RE 3 4E 0.61 -1.07 -0.53 -0.43 . - 28.96 -16.45 -14.13 -20.62 - 8.11 -5.79 P=23.12 [0-4 -0.19] 25.1; PET! 2317[2,4 +0.18 Add surfaces 586 for transverse 5 23.17 -0.45 loze -6.26 -0.45 bitte -6.26 -14.60 w w 2 3 til 9,6 (EW) tributary with FL 3 (w) 1 37 W 1 31 - Tributary wioth FL 3 5 AB D E F G H Identify lines 7 Het wt 37 of lateral 59 resistance and multiply est by trib Assume lines los are lines of resistance. Loading is based on a tributary wioth. For line , 411.4 Ref sit Wirth to pet 745, 990f MWANADA ANAAL 191.5 pef 402.9" B D PL 3 6 I Plti W W 437.3244 162. golf pel. plf 4913 92.5 Pril F23 The class to complete longitudinal analysis. Assume lines A-H are lines of resistance. Provide forces panels for lone) intenor lines A&H linec C; pti Precept lines B-G and poi 116 63% 1 Note on Wind loads on Buildings: MWERS Envelope Procedure Chater 28 diaphragma All bldo's have LERS in both orthogonal directions LERS for long loads LFRS for W, EQ Transverse loads wws wsze 6 stei zoo.c. Ji@ 140.6. 6/4.. 4'00 IN 0 w Plan View -Truss girder with two interior columns 2 A secnion 1-1 KA X 3 4, Ib TA' 4, PEKA. K=F/A The roof panel/assembly acts in the plane of the wof. out of plane as a diaphragm Transverse loading Longitudinal In-plane loading TICHI shear wall si-in-plane deflection 4 EX Det. A WFk loads using Enrelope pwedure . who warehouse Purlin length = 37' Precast concrete wall panels Purlin spacing = 80. open websteel joist Joist girders = 37'0.c. Roof: gable structure one story building 256 x 140 x zo' Location is st. Louis, Mo slope /: 12 Roof surface roughness: C topography: flat X 20 146 Plan LRidge at purlin (Jolst) THE HE -25.4" 11 WW2 5 MacBook Air 5 1 6 63% + WEH 937loc Review Table 20.2-) step procedure Elon 8 32o.c. IC + + 1. Risi cate gory Table 1.5-1 Assign Category Basic wind speed y 26.5-1 and 26.5-2 wind hazard map secrion 26.5.113 V = 107 mph Table 26.60) wind load parameters Directionality Factor Kd = 0.85 MWFRS and C&C 2. a. 6 / 6 KED, Directionality factor Exp c 6 b. Exposure category Seeron 26.7 Flat Ilg 26.8-1 6. Topographic factor Kzt = 10 d. Ground elevation factor ke sl.o Table 26.94 e. enclosure classification section 26.12 Enclosed BloG - STWcture f. Internal pressure coefficient Gp Table 26.13-) Gepi- & 0.18 for enclosed blogs 4. Velocity pressure exposure coefficient Kz or Kn Exp c/ki one variable ht O-IS 0.85 20 0.90 25 0.94 1 / 6 1. (. 26.- = ? (44 2011- 20 15 - Top 5. Velocin pressure for the Eq 0.85, + 4 k, . 24 4 4 4 4% 02 2 . 24. 913 L2 25-4 He (0+ 25, 233) 22.62 2 Cave 2 he r 4 0.85 ghorpe 21. 22.42 . 4o 20 173.17] 22.67 0.93 0.4T 23.42 2S 6, 18, 3-) 6. External pressure coefficient GCp 2 NOTE Edge zones transverse direction TAT 26 w 3E 30 ZE TE Roof angle Building Surfaces Fig 23.3-1 (GCpf) 2 3 4 4 7:12 0=2386 0.4 0.69.0.37 -0.29 0.61 -1.07 -0.53 -0.43 the diree non is pressure are direction is suction 0.5x hor. dim. parallel to direction of MW FRS) smaller Note 8 & 2.5x EH 1.07 3 6 -0.69 3 and 2E GEpf ore in zones 3 1 6 61% + 4.07 -0.69 Gepf ore in zones 3 and 2E 0.5x256 = 12e' ' 2.5x22,6% = 56.7' controls AWS 2 3 4 Windward hard Pag [GCpt - GCR IPPS TABETZ ctos Roof Plan () psf) 57 Surface 23.17 2 2 Gepf 0.4 -0.69 -0.37 -0.29 Piti) .10 -20.16 -12.74 -10.89 13.44 -(1.82 -4.40 -2.55 4 9.96 1330 4 12.30 15 RE 3 4E 0.61 -1.07 -0.53 -0.43 . - 28.96 -16.45 -14.13 -20.62 - 8.11 -5.79 P=23.12 [0-4 -0.19] 25.1; PET! 2317[2,4 +0.18 Add surfaces 586 for transverse 5 23.17 -0.45 loze -6.26 -0.45 bitte -6.26 -14.60 w w 2 3 til 9,6 (EW) tributary with FL 3 (w) 1 37 W 1 31 - Tributary wioth FL 3 5 AB D E F G H Identify lines 7 Het wt 37 of lateral 59 resistance and multiply est by trib Assume lines los are lines of resistance. Loading is based on a tributary wioth. For line , 411.4 Ref sit Wirth to pet 745, 990f MWANADA ANAAL 191.5 pef 402.9" B D PL 3 6 I Plti W W 437.3244 162. golf pel. plf 4913 92.5 Pril F23 The class to complete longitudinal analysis. Assume lines A-H are lines of resistance. Provide forces panels for lone) intenor lines A&H linec C; pti Precept lines B-G and poiStep by Step Solution
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