Problem 10: A contestant in a winter sporting event pushes an m kg block of ice across a frozen lake by applying a force F at an angle 0 below the horizontal as shown. Assume that the coefficient of static friction for ice on ice is 0.0300, and the coefficient of kinetic friction for the same is 10 0.0100. Let to the right be the positive x direction and up be the positive y direction for your equations. Part (a) Please use the interactive area below to draw a free body diagram to represent the situation when the contestant is pushing, but the force is not yet sufficient to start the block sliding. Use F, for the force of static friction and Fk for the force of kinetic friction if they are needed for your free body diagram. FBD : Force Labels: Fn, Fs, Fg, F, g, Fk, a, v Angle Labels: 45, 0, 90, 135, 180, 225, 270, 315, 0 Part (b) Enter an expression for the net force in the vertical direction, EFy. Your expression may include the mass, m, the acceleration due to gravity, g, the normal force, FN, the applied force, F, and the angle of the applied force below the horizontal, 0. Expression : EFE Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(), cos(0), sin(a), sin(), sin(0), Y, HK, MS. 0, F, FN, g, m, n Part (c) Enter an expression for the magnitude of the the normal force, FN. Your expression may include the mass, m, the acceleration due to gravity, g, the applied force, F, and the angle of the applied force below the horizontal, 0. Expression : FN Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(Q), cos(0), sin(a), sin(), sin(0), Y, HK, Hs, 0, c, F, g, m, n Part (d) Enter an expression for the magnitude of the applied force, F, at the threshold where static friction is at its maximum value. Your expression may include the mass, m, the acceleration due to gravity, g, the angle of the applied force above the horizontal, 0, and appropriate coefficients of friction. The friction coefficients are up and us. Expression : Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(), cos(0), sin(a), sin(q), sin(0), Y, HK, Us, 0, F, g, m, n, v Part (e) Obtain a numeric value, in newtons, for the magnitude of the maximum applied force, F, consistent with static friction when the force makes an angle 150 below the horizontal and the mass of the block is 25 kg. Numeric : A numeric value is expected and not an expression. F = Part (f) Please use the interactive area below to draw a best free body diagram to represent the situation when the block has started to accelerate from rest due to the contestant pushing on it. Use F, for the force of static friction and Fx for the force of kinetic friction if they are needed for your free body diagram. FBD : Force Labels: Fn, Fk, Fg, F, g, Fs, a, V Angle Labels: 45, 0, 90, 135, 180, 225, 270, 315, 0 Part (g) Obtain an expression for the acceleration of the block corresponding to the free body diagram from part (f). Your expression may include the mass, m, the acceleration due to gravity, g, the applied force, F, the angle of the applied force below the horizontal, 0, and appropriate coefficients of friction. The friction coefficients are uk and us- Expression : 1= Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(Q), cos(0), sin(a), sin(p), sin(0), y, HK, Us, 0, c, F, g, m, n Part (h) Obtain a numeric value for the acceleration, a, in meters per squared seconds, when the mass of the block is 25 kg and the angle of the rope is 150 below the horizontal. For the magnitude of the applied force, use the threshold value obtained in part (e). Numeric : A numeric value is expected and not an expression. m/s2 All content . 2023 Expert TA, LLC