Problem 2: 2013 Second Hour Exam: Problem 2: Spring Block Drop (30 points) spring block m y=0 Ymin A block of given mass m is released at rest at a position y = 0 where it is connected to an ideal spring with a given spring constant k. At the release, the spring is at its equilibrium position (neither compressed nor extended). Once released, the block falls vertically and the spring - stretches. Part (a) 10 pts: What is Ymin corresponding to the minimum position of the block after release? Express your answer in terms of the given parameters. Explain your work. Hint: Note that ymin is negative. Part (b) 10 pts: - What is the magnitude and direction of the acceleration of the block when the block is at the position Ymin as calculated in Part (a)? Express your answer in terms of the given parameters. Explain your work. Hint: no, the acceleration here is not zero. Part (c) 10 pts: What is Ymax, corresponding to the position of the block when it has maximum speed? Express your answer in terms of the given parameters. Explain your work. Hint: You do not need to find the actual value of the maximum speed. Also Conservation of Energy is not what you want. Instead, think about the net force on the block as a function of position.