Problem 2: Consider the memory and registers representation below, where each cell has an address (first row has addresses 0 to 7) and a stored value. Assume that this computer has a load instruction which always loads values to the accumulator. The instruction has the following fields: first 4 bits are the LOAD operation code (A16), the next 3 bits are a register number and the remaining 5 bits could be a constant, offset or address. If the instruction in hexadecimal is A35, show the value that was loaded in the accumulator Address (Decimal) Memory Registers R0 5R43 RI= | 2 | R5-11 0 13 15 17 19 21 23 25 27 8 2 4 6 8 10 12 16 18 R2-0. R6=| 4 | 16 | 3 | 6 16 36 9 12 13 04 11 27 12 13104- 11127. 24 28 26 24 23 16 19 12 24 Addressing mode Accumulator result Addressing mode Accumulator result Direct Immediate Indirect Register indirect