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PROBLEM 2: Recall that according to Poiseuille's law, the flow resistance in a tube of circular cross section is given by: R= 8nl (a)
PROBLEM 2: Recall that according to Poiseuille's law, the flow resistance in a tube of circular cross section is given by: R= 8nl (a) Calculate the flow resistance, R, for a horizontal tube of radius r = 0.050m and length = 50.0m carrying oil (n = 0.12 N s/m). Hint: You will get R =2.445 x 10 Pa-s/m if done correctly. (b) Calculate the flow resistance, R2, for a horizontal tube of radius 72 = 0.040m and length l = 50.0m carrying oil (0.12 N s/m). The two tubes in Parts (a) and (b) are joined in series (as shown below), to make a tube 100.0m long. 1- Pi T1 P2 = 101 kPa AV = 850 cm/s At (c) What pressure (pi) is required to generate the indicated volume flow rate?
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Mechanics of Materials
Authors: James M. Gere, Barry J. Goodno
7th edition
495438073, 978-0495438076
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