Problem 2 Three charges are at the corners of an isosceles triangle as shown in the gure below. The 3:530 110 charges form a dipole. +SDUpC R \\ '\\2enun \\ \\ \\ \\ 1,HHMpC / / / 2/100 cm I I I I | 3.00 cm I I | I | I I (a) Find the force (magnitude and direction) the 1l].OU 11C charge exerts on the dipole. (b) For an axis perpendicular to the line connecting the 3:530 110 charges at the midpoint of this line, nd the torque (magnitude and direction) exerted on the dipole by the 1l].l]l] 11C charge. (b) Now we must consider the forces acting on the two charges that make up the dipole. Reversing the directions of F1 and F2 and having them act on the charges of the dipole gives us the following diagram: The horizontal components of the forces F1 and F2 contribute to the torque on the dipole and cause it to rotate in the clockwise direction. Furthermore, the angle 6 as indicated in the gure is the same angle 6 as given in the gure for part (a). The torque contribution due to the top force F1 is 1'1 = $51 cos 9 3 F1 \\lri' 32/42 2 r _ (3.00 x 10-2 m} (1.12 x 103 N) (2.00 cm)2 (3.00 cm}2f4 _ 2 2.00 em = 11.1 N - m. The torque contribution due to F2 is equal in magnitude and points in the same direction as the torque 7'1. Therefore, the net torque on the dipole is 7:271 =22.2N-m