Problem 3 A square loop of side length 2a=0.03m has one corner y = a 1=X inside a region (dotted area in the picture) with a ho- mogeneous magnetic field By of 2T pointing out of the page. The wire of the loop crosses the x- and y-axes at x = -a X = a points (x=+a, y=0), (=-a, )=0), (x-0, y=ta), (x-0, y=-a). The resistance of the loop is 59. Bi If the loop is pulled out of the magnetic field region at a O velocity of 3m's directed along the +x-axis, calculate: a) The induced EMF in the loop once it starts moving. E. J- do. .1- dlay8, co'). adB, = Q UB, = 0015m ber 2T dt > E = 0.09 V b) The value of the induced current in the loop and the direction of its flow. Chin's Low: E= R Ind - Iind= 0.09/50 = 0.018A decrening - need Bind parallel to B, I'd must be counterclockwise c) If the loop is pulled out of the magnetic field region still at a velocity of 3m/'s but this time di- rected along the y-axis, will the induced current in the loop change in value or direction? Justify your answer. It will not: ff-side The . 2 ( xa Bund ") = & a B, = VaB,= 0.09- I.: Q.018A Because I is gain decreasing - Inid is spam counterdackwine. The wire loop is now pulled out of the magnetic field region at a velocity of 3m/s along the y=x line (showed in the picture above). (Note: the wire loop is kept in the plane of the page.) d) Determine the magnitude and the direction of flow of the induced current in the loop. 8 = 1 do = d ( x y B , cool " ) = x dy B, + dx y B, = XV B, + vyB, = ( X+y ) VB, x = art & y = a_ut > E= (avt+a-vt) UB= (29-20+)VB, is trine dependent ! Because Do in gani decreasing - I mis rigamenumberdudesite. I ' (t ) : 2 ( 9 . Ut ) VB