Problem 3 The center of square ABCD is the origin 0 = What algebraic calculation confirms this? Now consider the equations that transform a vector y = Z= [bh] Y2 Gy, where %1 = 31 32 Z2 = -2y1 into the vector z = G = [2] [1] -2 What is the center of A'B'C'D'? . We can abbreviate this transformation as