Problem 4: Activation energy (7 pts) Many physical processes can be modeled by an exponential equation. For example, chemical reaction rates depend on a reaction-rate constant that's a function of temperature and activation energy . R univorsal gas constant, 8.314k.J/kmol K. Q activation energy, in kL/knol, . T-temperature, in K, and . ko = constant that depends on the reaction. We can find the values of ko and Q from the following cquation, In(k) = ln(k) ) R T since the equation has the frin y = az + b with y = In(k),= % and b-n(ko). ,a = Consider T,K k,s1 200 1.46r10 00 0.0012 600 0.0244 800 0.1099 1000 0.2710 Plot the data with on the x-axis and In(k) on the y-axis. Use the polyfit function to find the slope of your graph, d the intercept, In(k Calculate the value of Q and ko