Problem 4: Using special techniques called string harmonics (or "flageolet tones"), stringed instruments can produce the first few overtones of the harmonic series. While a violinist is playing some of these harmonics for us, we take a picture of the vibrating string (see figures). Using an oscilloscope, we find the violinist plays a note with frequency f= 785 Hz in figure (a). ..... Part (a) How many nodes does the standing wave in figure (a) have? Numeric : A numeric value is expected and not an expression. N= Part (b) How many antinodes does the standing wave in figure (a) have? Numeric : A numeric value is expected and not an expression. Part (c) The string length of a violin is about L = 33 cm. What is the wavelength of the standing wave in figure (a) in meters? Numeric : A numeric value is expected and not an expression. Part (d) The fundamental frequency is the lowest frequency that a string can vibrate at (see figure (b)). What is the fundamental frequency for our violin in Hz? Numeric : A numeric value is expected and not an expression. f= Part (e) In terms of the fundamental frequency . what is the frequency of the note the violinist is playing in figure (c)? Expression Select from the variables below to write your expression. Note that all variables may not be required. P. y. 0, b, c. d. f1 . g. h, j. k, m, n, P. S Part (f) Write a general expression for the frequency of any note the violinist can play in this manner, in terms of the fundamental frequency fy and the n, the number of antinodes on a standing wave. Expression