Problem #5: [2 marks] "Which of the following is equivalent to the surface area of rotation of the function y = = on the interval 1 1. [2 marks] (A) (1)" -6 . 11 . 16 . ... . (5n -4) (B) (-1)" 6 . 11 - 16 . ... . (57 - 6) (-1)5 - 10 . 15 . ... . (57 -5) 3" n! 5" n! (D) (-1)" 6 . 11 . 16 . ... . (5n -4) (E) (-1)?-15 . 10 . 15 . ... . (57 - 5) ( F ) (-1)" -14 . 9 . 14 . ... . (5n - 4) 5n n! 50 -1 n! 50 n! (G) (1)-4 . 9 . 14 . ... . (5n - 6) (H) (-1)"4 . 9 . 14 . ... . (5n - 6) 5" n! 50 -1 n! Problem #6: Select v Save Problem #7: If f(x) is a solution of y' = (+ 3) [2 marks] ; and f(1) = 0, then find f(e). (A) - (B) = (C)0 (D) 1 (E) 3 (F) 3e + 2 Problem #7: Select v