Problem 5. A certain town has 250,000 families, of which 25,000 do not have a TV at home. As part of an opinion survey, a simple random sample of 900 families is chosen. What is the chance that between 9% and 11% of the sample families will not have a TV at home? [This is a straightforward problem on the CLT for binomial distribution; the answer is P(|Z| < 1) 0.68]