The reaction NABH4 (aq) + 2H2O-4H2 + NABO2(aq) has been considered as a means of generating H2 to power small fuel The reaction is catalyzed by Ru supported on an ion exchange resin. No reaction takes place in the absence of the catalyst. In an experiment in an ideal, isothermal batch reactor, 0.25 g of 5 wt.% Ru/IRA-400 resin was dispersed in an aqueous solution containing 6 g NaBH4, 3 g NaOH, and 21 g H2O. The following data were obtained at 25 C. cells. Cumulative amount of Time (s) H2 generated (1@STP) 0.00 500 0.31 1000 0.62 1500 0.93 1. What is the fractional conversion of NaBH, at 1500 s? 2. The reaction is claimed to be zero order overall, and zero order with respect to each of the reactants. If this is true, what is the value of the rate constant at 25 C? 3. Is it reasonable to conclude that the reaction is zero order based only on the data above? Explain your answer. 4. ACSTR that operates at 25 C and generates 1l of H/min is to be designed. The feed will be an aqueous solution of NaBH and NaOH, with the same NaBH/NAOH/H O ratio shown above. If the conversion of NaBH4 in the effluent is 75%, how much catalyst must be in the reactor? (You may use the zero- order assumption for this calculation.)