Problem 7 loop 1 Part A: 12 V Look at the circuit in the picture and answer the following question: 30 loop 2 6 V a) Write down two equations by applying Kirchhoff's loop rule to the two loops in the picture. loop I : AV = 0 = 12V- 6013 - 3021, - 0= 4V-281,-LLI,#, loop 2 : AV = 0 = - 6V - 12V+ 3021, + 91212 - 0=-6V+INI,+ 352I,#,) b) Find the numerical values for the current Iz. Node rule : I, = In + I, > (*) 0 = 4V- 252 1, - IN I2- 1Is. 0 = 4 V - 31 I, - IN I 2 - Ig = 4V-INIz 3n O = - 6 V + 12 I , + 12 In + 31 12 O = - 6 V + ( 4 4-152In ) + 452Iz O = = 18 V + 4 V + In I , + 12 5 Iz Part B: 0 = - 14 V + 1 1 52 Iz WW I2 = 14 A : 1. 27 *