Problem 7 PART A: A light beam is initially unpolarized, and it passes through a polaroid filter with a horizontal axis. The intensity of the light beam before passing through the polarizer is 10=3W/m2. a) What are the intensity /1 and the angle of polarization of the light beam as it emerges from the other side of the polaroid filter? Unpolarized to polarized: 1 = 710 = ~ X 3- m 2 = 1.5- m 2 along horizontal After the first polaroid filter, the light hits a second filter with its axis at 10 from the horizontal. b) What are the intensity /2 and the angle of polarization of the light beam as it emerges from the other side of the second polaroid filter? Malus's Law: I2 = I, cos (0)]2 = 1.5-W [cos (10.)]2 = 1.45-2 10 from the horizontal A third polaroid filter with its axis at 30 from the horizontal is placed after the second filter. c) What are the intensity /3 and the angle of polarization of the light beam as it emerges from the other side of the third polaroid filter? Malus's Law: 13 = 12 [cos (0)]2 = 1.45-W [cos (30 - 109)] = 1.28- 30 from the horizontalProblem 4 A light beam is initially unpolarized, and it is passed through a Polaroid filter which is oriented with its axis parallel to the horizontal. The initial intensity of the light beam before entering the Polaroid filter is 12W/m2 a) What is the intensity of the light beam after passing the Polaroid filter? The light going through the filter is unpolarized; therefore, the intensity of the light after passing through filter #1 is /1 = 710 = - X 12- = 6- m2 m2 b) What is the polarization direction of the light beam after passing through the Polaroid filter? After passing through the filter, the direction of polarization of the beam will be parallel to the axis of the filter, i.e. along the horizontal. We place a second Polaroid filter after the first one. This second filter is oriented with its axis at 150 with respect to the vertical. c) What is the intensity of the light beam after passing through the two filters? 12 = 1 [cos (0 )]" = 6-W2 cos (90 - 15) =6 W cos (75) = 0.40-W m 2 d) What is the polarization direction of the light beam after passing through the two filters? After passing through the second filter, the direction of polarization of the beam will be parallel to the axis of the second filter, i.e. at 15 with respect to the vertical. We now want to turn the second filter so that the intensity of the light beam is reduced to zero after passing through the two filters. e) By how much should we turn the second filter from its original position so that this can occur? We need to turn the second filter so that its axis is perpendicular to the axis of the first filter. Because the axis of the first filter is along the vertical, to achieve this we need to turn the second filter by 15 toward the vertical direction