PROBLEM A 12.6-V battery is in a circuit with a 30.0-mH inductor and a 0.150- resistor, as in Figure 20.27. The switch is closed at t = 0. (a) Find the time constant of the circuit. (b) Find the current after one time constant has elapsed. (c) Find the voltage drops across the resistor when t = 0 and t = one time constant, T. (d) What's the rate of change of the current after one time constant? a. ) T = - T= (30.0 mHX- 1000 mH Two.2s 0.150 n b.) I=E Clue ? ) I= 12.6V 0.150 A CI-e 0.25) In 53.IA at=Os C.) mm SV= OV OV= Ubatt " Vind-VR VR= Esupplied Eback VA= 12.6V-12.6V VR=OV @t=0 dI -o @ t= 16= 0.2s EV= OV OV= Vbatt Vind VR VR= Esupplied "Eback VR= 12.6V-L VR= 12.6V-L DE VR= 12.6V- (30MAX 53.IA-OA It VR= 12.6V-(30MAX IH 53.IA-OA 0.25 VR @t= 1t is - 4.635V