Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Problem i 33% It is mentioned in Chapter 7 of ISL that a cubic regression spline with one knot at &can be obtained using a
Problem i 33%" It is mentioned in Chapter 7 of ISL that a cubic regression spline with one knot at &can be obtained using a basis of the form z, r2,T3, [r- ] , where Iz-d-(z-E)3 if z > and equals 0 otherwise. We will now show that a function of the form is indeed a cubic regression spline, regardless of the values of ??-??2?,?4. 1. Find a cubic polynomial such that f(z)-fi (z) for all z 2. Find a cubic polynomial ?. Express aib,,ci,di ?n terms of%,AAnAsA. such that f(x)-fa(z) for all ! > . Express a2.h,c2-d2 in terms of A-A.h.h'?, we have now established that f(x) is a piecewise polynomial 3. Show that fi (E)-fg(E). That is, f(x) is continuous at ?. Problem i 33%" It is mentioned in Chapter 7 of ISL that a cubic regression spline with one knot at &can be obtained using a basis of the form z, r2,T3, [r- ] , where Iz-d-(z-E)3 if z > and equals 0 otherwise. We will now show that a function of the form is indeed a cubic regression spline, regardless of the values of ??-??2?,?4. 1. Find a cubic polynomial such that f(z)-fi (z) for all z 2. Find a cubic polynomial ?. Express aib,,ci,di ?n terms of%,AAnAsA. such that f(x)-fa(z) for all ! > . Express a2.h,c2-d2 in terms of A-A.h.h'?, we have now established that f(x) is a piecewise polynomial 3. Show that fi (E)-fg(E). That is, f(x) is continuous at
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started