Problem II The Rutherford gold foil experiment provided evidence that the atom consisted of a very small, dense nucleus. The experiment collided a beam of alpha particles into what we now understand are gold nuclei. An alpha particle is a Helium-4 nucleus consisting of 2 protons and 2 neutrons. The alpha particles were created from the decay of Radon-222 nuclei. The alpha particles are emitted with an energy of 5 .49 MeV. The units of energy \"MeV\" stand for mega electron volts or 106 electron volts. The electron volt is the amount of energy an electron gains if it moves through an electric eld such that it gains 1. 602 x 1019}. In other words, the value of the fundamental charge, 6, in Joules. If the alpha particle collides traveling directly at the gold nucleus, what is the closest distance the alpha particle approaches? The energy ofthe alpha particle in Joules is 5. 49 x 10'6 - je| = 8.79 x 1013]. Assume the gold nucleus is xed in place due to it being a part of the foil of gold