Problem: Report Error Given a square matrix A, the characteristic polynomial of A is defined as PA(t) = det(tI - A), where I is the identity matrix. For example, if 2 A = , then the characteristic polynomial of CO 4 A is PA(t) = det(tI - A) = det (t (8 9) - (3 and rewriting the difference as a single matrix, this becomes det = (t-1)(t -4) -(-2)(-3) =12 -5t-2. (a) Compute the characteristic polynomial of the matrix A Express your answer in the form patz + pit + po. (b) For the polynomial in part (a), find P2 A2 + PIA + Pol