Problem with capacitors discharging and charging close switch When the switch is closed at =0s, the capacitors in the fig- ure are charged. 402 > 250 10UF a) What is the time constant of this circuit? 30UF TERE 150 40UF Rea = (+ + you + 2 5 + 15R = 30. 382 Rach = 2512 + 30: 382 = 55. 3852 100 150 = 20 NF 55:3852). 0011076 8 BONET lack b) At what time has the current in the 150 resistor decayed to half the value it had immediately after the switch was closed? In(1 , ) = = I - RCla ( /2 2 ) = T - (.801 1076 sec ) 10 ( 1 /2 ) = |7+ 677 *10 see 9V A 9V battery is added to the circuit as shown in the picture. If the capacitors are not charged, right after the battery is connected ... 409 250 30 UF OUF c) What is the initial current through the 150 resistor?? I = AV 150 40UF 5 5:380 40 . 1625 A 100 150 d) How long does it take for the current to drop to 1/e times its initial value? 10 (' /e) = = I RC T= - RelAlle) T= -( 55:38,) ( 20 pt) In( 16*vo- 19) = - 47935 ms or -1 047 see