Procedure A Measured system mass M 2103 kg + 0.0001 kg Proportional error in M.0DO.476 Initial value of m, .1 103 kg Initial value of m, 1003 kg Initial mass difference Am .100 kg + 0.0002 kg Proportional error in Am 0.02 1, (s ) v, (m/s) t, (s) v2 (m/s) a (m/s?) 1. 862 0. 41 2.000 0. 46 0: 3623 0801 0. 46 $ 129 0 . 256 .3.354 0. 403 0.40 1.011 0 . 59 -3125 0. 604 0.59 11. 014 10 - 72 - 3171 mean value of a .3318 m/s2 sample standard deviation in a .02260 m/sz standard error in the mean for a 201 13 m/s2 Value of n from Table I-1 for 90 % confidence level and 4 data 2. Uncertainty in a -02712 m/s proportional error in a 8174 Amg .098 N uncertainty in Amg 20096 N Ma .6978 N proportional error in Ma .0822 uncertainty in Ma .205737 N calculated friction force f .02822 N uncertainty in f .000462 N 3-9Procedure B Table for Additional Measurements m, (kg) m, (kg) Am (kg) t , ( s ) v, (m/s) t, (s) V2 (m/s) dexp (m/s2) . 1 103 . 1003 0160 1.862 41 2.000 1 46 - 3623 - 1203 10903 . 0200 1.077 041 10276 . 65 1.206 . 1303 .0803 . 0300 : 375 1.552 1.54 2.090 . 1408 0 0703 .D400 571 0. 63 10-577 1, 16 2. 849 1 1503 . 0603 6500 2.806 3. 18 1061 30846 Note: Transcribe the data from Part A into the first row of the table above and include that point in your graph. lanochogor ! 5000.0 Note: Include appropriate units in your answers below. slope of graph calculated system mass (from slope) percent error in calculated system mass horizontal intercept of graph O calculated friction force (from intercept) O Does the value of the friction force resulting from this calculation lie within the range (calculated value plus or minus uncertainty) for the friction force that you found in Procedure A? 3-10Additional Questions: 1. For any one mass difference use Equations (3-6) (a&b) to find (a) the tension in the string above the descending mass m, and (b) the tension in the string above the ascending mass m2. [Remember to include units.] Record those tensions as answers 'a' and "b' in the blanks below. Indicate which mass difference is being used and show your work in the space below the answer blanks. a ) b ) or posits tout : relative motion The w granthide of the force depends on only punch of the force of contact between is represented by in upper-care 2. One more calculation of the friction force: f= T, - T2 . Display your calculation and results below. Again, include units. both the notyaa fare exerted on an ice what we can solve Equal 3. How do your three values of the friction compare with one another? If the three values differ by "much", why do you think that happened? [Note that all three values should be very small. The differences, ideally, should be even smaller.] 3-11