Proceed as in Example 4 in Section 11.3 to find a particular solution xp(t) of equation (11) in Section 11.3 m when m= dx dt2 +kx = f(t) (11) k = 4, and the driving force f(t) is as given. Assume that when f(t) is extended to the negative t-axis in a periodic manner, the resulting function is even. f(t) = 2t-2, 0