Processing times are given in hours in the following table J2 J J2 J3 Among J5 J Jobs J J3 33 Js M 10 2 al 2 Jobs J3 18 6 Solution The minimum processing time among all the jobs in the 2 machines M and M is 2 which is marked in under lined bold face which correspond to the job 12 on machine M Thus the job J2 is placed sequenced in the first position in the sequence 20 We are now left with 4 jobs and their processing times are given below Machines M M M 4 12 16 6 6 10 18 20 those four minimum jobs the processing time between the two machines is 4 which corresponds to the job J on machine M Hence the job J is placed in the last position in the sequence shown below 4 14 J 18 16 6 The remaining 3 jobs and their processing times are given below Machines M M 14