Production of recombinant protein by a genetically engineered strain of Escherichia coli (E.coli) is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CH1.55O0.31N0.25. The yield of cell biomass from glucose is measured at 0.48gg1 and the yield of recombinant protein from glucose is about 20% that for cell biomass. The cell biomass molecular formula is given as CH1.77O0.49N0.24. a. Write the stoichiometry equation and determine the stoichiometry coefficients for each components. b. Calculate ammonia and oxygen that are required for the cell growth? (15 marks) (10 marks) c. If the biomass yield remains at 0.48gg1, how much ammonia and oxygen are required for the wild-type E. coli that cannot synthesize recombinant protein? (10 marks) Molecular mass (g/mol) : Glucose, C6H12O6=180 Biomass, CH1.77O0.49N0.24=25 Recombinant protein, CH1.55O0.31N0.25=22.03