Production of single$-$cell protein from hexadecane is described by the following reaction equation: C$16$H$34+$ a O$2+$ b NH$3=$ c CH$1\mathrm{.}66$ O$0\mathrm{.}27$ N$0\mathrm{.}20+$ d CO$2+$ e H$2$O where CH$1\mathrm{.}66$ O$0\mathrm{.}27$ N$0\mathrm{.}20$ represents the biomass. RQ $=0\mathrm{.}43,$ determine the stoichiometric coefficients. If the biomass contains $5\%$ ash, calculate $($a$)$ calculate the yield of biomass from hexadecane $($b$)$ the maximum possible yield of biomass.