professor at a local university noted that the exam grades of her students were normally distributed with a mean of 82 and a standard deviation of 6. Everyone who made above the 89.97^thpercentile score was given an A. Whatexam gradehad only 10.03% of students earning at or above it? Hint: use the z-table to find the corresponding z-score that has a probability of 0.1003 to its right and solve for the X value that would produce that z-score.