PROGRAM $5$: Real Big Number!

Write an HLA Assembly language program that prompts for n$,$ an int$8$ value, and then displays a repeated digit pattern starting with that number. The repeated digit pattern should print all the values from $1$ up to n then all the values from $1$ up to n$-1$ then all the values $1$ up to n$-2...$ then all the values $1$ up to $2$ and end with a single $1.$ Shown below is a sample program dialogue.

Gimme a decimal value to use for n: $5$

Here's your answer: $123451234123121$

Gimme a decimal value to use for n: $8$

Here's your answer: $123456781234567123456123451234123121$

$($Hint: The digit pattern is too large to store into any datatype we have learned to date so I am expecting that you will use a loop with CMP instructions and a conditional jump to print individual digits, rather than store the complete number in a variable, just like the sample programs in this unit demonstrate$)$

$($Additional Hint: You should not be using high language statements like for, while or repeat loops, as these are not assembly instructions are off limits in this course.$)$

Withoug using high level programming such as loops and if statements.

Here is my c code that works but want to convert to HLA assembly

#include

void printDigitPattern$($int n$)\{$

int i$,$ j;

for $($i $=1$; i $<=$ n; $++$i$)\{$

for $($j $=1$; j $<=$ i; $++$j$)\{$

printf$("\%$d$",$ j$)$;

$\}$

$\}$

for $($i $=$ n $-1$; i $>=1$; $--$i$)\{$

for $($j $=1$; j $<=$ i; $++$j$)\{$

printf$("\%$d$",$ j$)$;

$\}$

$\}$

printf$("1$

$")$; $//$ End with a single $\text{'}1\text{'}$ and newline

$\}$

int main$()\{$

int n;

printf$("$Gimme a decimal value to use for n: $")$;

scanf$("\%$d$",$ &n$)$;

printf$("$Here$\text{'}$s your answer: $")$;

printDigitPattern$($n$)$;

return $0$;

$\}$

Heres the code i have but error at line $20$

program RealBigNumber;

#include$("$stdlib$.$hhf$")$

static

n: int$8$;

i: int$8$;

j: int$8$;

begin RealBigNumber;

$//$ Prompt user for input

stdout.put$("$Gimme a decimal value to use for n: $")$;

stdin.get$($n$)$;

$//$ Print the pattern

stdout.put$("$Here$\text{'}$s your answer: $")$;

$//$ First half: from $1$ up to n

mov$(1,$ i$)$;

FirstLoop:

cmp$($i$,$ n$)$;

jg$($EndFirstLoop$)$;

mov$(1,$ j$)$;

InnerFirstLoop:

cmp$($j$,$ i$)$;

jg$($EndInnerFirstLoop$)$;

stdout.put$($j$,"")$;

inc$($j$)$;

jmp InnerFirstLoop;

EndInnerFirstLoop:

inc$($i$)$;

jmp FirstLoop;

EndFirstLoop:

$//$ Second half: from n$-1$ down to $1$

dec$($n$)$;

SecondLoop:

cmp$($n$,1)$;

jl$($EndSecondLoop$)$;

mov$(1,$ j$)$;

InnerSecondLoop:

cmp$($j$,$ n$)$;

jg$($EndInnerSecondLoop$2)$;

stdout.put$($j$,"")$;

inc$($j$)$;

jmp InnerSecondLoop;

EndInnerSecondLoop$2$:

dec$($n$)$;

jmp SecondLoop;

EndSecondLoop:

$//$ End with a single $\text{'}1\text{'}$

stdout.put$("1$

$")$;

end main;