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Project A: The internal rate of return i is the solution of the equation 1;000;000 270;000a8 14 0 at rate i which gives i 14

Project A: The internal rate of return i is the solution of the equation 1;000;000 270;000a8 14 0 at rate i

which gives i 14 0.2120 or 21.20%. Project B: The internal rate of return i is the solution of the equation

1;200;000 20;000a3 1;350;0005ja3 14 0 at rate i which gives i 14 0.1854 or 18.54%.

how did he found the IRR for both projects?

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