Projectile Motion Simulation Go to https:x'..iphet.co|orado.ed .Ifsimsfhtrnlx'projectiIe-rnotion,-'|atesb"projectile-motion_en.htm| Part 1 Go to the "Intro" modu|e_ Maintain the horizontal position of the canon and the initial launch speed of 15 mfs. Change the height of the cannon to '15 m. Start with no air resistance. Click on velocity vectors "cgmponenrjl" At the bottom of the screen. click on "slow" rather than "normal." Ignore the target for this exercise. Launch the projectile. 1. What do you notice about the horizontal component of velocityr as the projectile moves along its trajectory? Explain why this is. 2. What do you notice about the vertical component of velocity as the projectile moves along its trajectory? Explain why this happens. Reset the simulation and click on the acceleration vectors "components" for the same initial conditions. 3. What do you notice about the acceleration vector components [both vertical and horizontal}? Explain why this is. 4. Launch the projectile at the following speeds [with no air resistance} and fill in the table {Use the data collector at the upper right by dragging the crosshairs over the last point of the proiectile's trajectory}: Initial Speed 5. How does initial horizontal velocity effect the range of the projectile? 5. Why does the time to the ground not change with a change in initial horizontal velocity? Part2 Now. leave the " Intro" module and go to the "Vectors" module. The tannen should be en the around rather than on a platform. Click off air resistance for now. Set initial speed at 20 mfs. To launch the projectile straight up. set the angle of the canon to 9:) degrees. Click on "gmw" at the bottom of the screen. Click on the velocityr and acceleration vectors. LEUF'ICh the lCPTC'lEC'EilE- {You mavr have to zoom out to observe the projectile's entire path.j I". Describe the velocityr and acceleration vectors throughout the trajectory. Explain whv. [You mav want to run the simulation with onlv the velocitv vectors clicked on and a second time with onl'jr the acceleration vectors clicked on.} B. To what height does the projectile reach? How long did it take for the projectile to reach the top of its path? How long did it take for the projectile to come back down from the top of its path? Was this the same amount of time it took for the projectile to reach the top of its path? Launch the projectile with an initial speed of 15 Ws with no air resistance from the various angles below and record the data: ' '25 degrees 9. Time to top [5} Peak of TrajectoryI Time to bottom of Range of Trajectoryr . lrni path [Si [ml 80 degrees | ' :55 degrees 1 45 degrees l l 10. When a projectile is launched at an upward angle [with negligible air resistance]. the time it takes to reach the top of its path is the time it takes for it to come Izra cl: down. a. less than h. more than c. equal to 11. Explain the physics underlying your answer to #10. Reset the initial conditions to those used for questions #F' 5-: #8. but click on air resistance this time. Launch the projectile. 12. Why did the projectile not go as high in this case? Now, set the cannon at angle at 80 degrees and the initial speed to 15 m/s. Launch the projectile without air resistance, and then, launch it with air resistance. 13. Qualitatively, what effect did the air resistance have on the trajectory of the projectile? Why is this