prompt help

Ifyou have 300 meters of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area you can enclose? Area = 1" (include units) HINTS: Keep in mind that you do not need fencing on the side of the wall. If we assume the dimensions of the rectangle are L by W, the area of tlie region is A = LW The perimeter of the region is P= ...... + ............ (Here you should be adding all the sides) A javalina rancher wants to enclose a rectangular area and then divide it into five pens with fencing parallel to one side of the rectangle (see the figure below). There are 830 feet of fencing available to complete the job. What is the largest possible total area of the five pens? Largest area = (include units) HINTS: Let x represent the length of the entire rectangle and y represent the height. The area of the rectange is : A= xy The total fencing needed to create the given figure: (add up all the sides, including the interior sides, since fencing will be needed there as well) = 2x + ..y NOTE: When entering the units, leave a space between the numerial value and the units. Also, enter fr^2 using equation editor for the squaring portion.X X A rancher has 600 feet of fencing with which to construct adjacent, equally sized rectangular pens as shown in the figure above. What dimensions should these pens have to maximize the enclosed area? T = y Maximum area = HINT: To find area, multiply the outer dimensions (length and width) of the entire rectangle. To find total fencing needed, add up all the lengths of all the sides, including the sides of the inner regions. Note: Since x is the length of an inner rectangle for this question, A = (2x) yA parcel delivery service will deliver a package only if the length plus the girth (distance around, taken perpendicular to the length) does not exceed 104 inches. Find the maximum volume of a rectangular box with square ends that satisfies the delivery company's requirements. Maximum Volume = in?. HINT: If we assume that the dimensions of the box are L, W, W (square cross-section), then the Volume of the box is the product of all the Length Girth dimensions. Length plus Girth = L + 4W (Girth is the perimeter of the cross section.)Ajavalina rancher wants to enclose a rectangular area and then divide it into four pens with Fencing parallel to one side of the rectangle (see the gure below). He has 1000 feet of fencing available to complete the job. What is the largest possible total area of the four pens? W Note: you can Click on the image to get a enlarged View. Largest area = f f1;2 A box with a square base and open top must have a volume of 171500 cm3. Find the dimensions of the box that minimize the amount of material used. base length = cm height = cm HINT: If we label the dimensions of the box as X, X, H: (Since it has a square base, chose length = width = X ) The Volume of the box is, V = (X^2)(H) (The product of all the dimensions) The Surface area = Area of the Base + Total Area of all 4 Sides = X^2+