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= Protons having a kinetic energy of 5.16 MeV (1 eV = 1.60 x 10719 1) are maoving in the positive x direction and
= \" Protons having a kinetic energy of 5.16 MeV (1 eV = 1.60 x 10719 1) are maoving in the positive x direction and enter a magnetic field B = 0.051 6k T directed out of the plane of the page and extending from x = 0 to x = 1.00 m as shown in the figure below. =1.00m ; sepolsssea - @ {a) Ignoring relativistic effects, find the angle @ between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field. 171 x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. (b) Calculate the y component of the protons' momenta as they leave the magnetic field. 8.23E-21 % The response you submitted has the wrong sign. kg - m/s
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