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Prove by induction on n that the solution to (3.1) with the base case f(0) = 0 is f(n) = 2 - 1 f(n) =

Prove by induction on n that the solution to (3.1) with the base case f(0) = 0 is

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f(n) = 2" - 1 f(n) = 2" - 1

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