Prove/ disprove: If there are two solutions to X = X1V1 + x2V2+ ... + CnVn then % = {v1, V2, ..., Vn} is not a basis. (Your answer will be graded and scored after the due date)Prove / disprove: If % = { V1, V2, ..., Vn} is a dependent set of vectors, there are infinitely many solutions to X = @1V1+ $2V2+ ... +anVnExplain why if there are two solutions { x1, X2, ..., In } to .X = X1V1 + x2v2+ ... + CnVn then there are infinitely many solutions. (Your answer will be graded and scored after the due date)Suppose 9 = {v1, V2, ..., Vn} is a set of nonzero vectors, and let X = Q1v1 + a2v2 + ... + anVn and also X = biv1 + b2v2 + ... + bnVn where at least one bi * a; Explain why this means 0 = CIV1 + C2V2 + ... + CnVn .for some c;, where at least one c; 0. (Your answer will be graded and scored after the due date)