Question
public class Lab03P3Wrapper { public static boolean isValidSudoku(char[][] board) { /*ADD YOUR CODE HERE*/ int n = 10; int[][] row=new int[n][n]; int[][] col =new int[n][n];
public class Lab03P3Wrapper { public static boolean isValidSudoku(char[][] board) { /*ADD YOUR CODE HERE*/ int n = 10; int[][] row=new int[n][n]; int[][] col =new int[n][n]; int[][][] square=new int[3][3][n]; for(int i=0;i<9;i++) { for(int j=0;j<9;j++) { if(board[i][j]=='.')continue; int num = (board[i][j]-'0'); row[i][num]++; col[j][num]++; square[i/3][j/3][num]++; if(row[i][num]>1){ return false; } if(col[i][j]>1) { return false; } if(square[i/3][j/3][num]>1) { return false; } } } return true; } public static void main(String[] args) { char[][] board ={{'5','3','.','.','7','.','.','.','.'} ,{'6','.','.','1','9','5','.','.','.'} ,{'.','9','8','.','.','.','.','6','.'} ,{'8','.','.','.','6','.','.','.','3'} ,{'4','.','.','8','.','3','.','.','1'} ,{'7','.','.','.','2','.','.','.','6'} ,{'.','6','.','.','.','.','2','8','.'} ,{'.','.','.','4','1','9','.','.','5'} ,{'.','.','.','.','8','.','.','7','9'}}; System.out.println(isValidSudoku(board)); // Dummy Return } }
For the problem solved above, answer the following items:
What is the running time of the algorithm implemented? Explain your thought process behind the implementation
Describe in detail the running time breaking down each part of the code implemented into its respective runtimes
Does this code have a more optimal solution than the one implemented? If so, explain why, how and what would you change from your code to optimize said solution
If your code does not meet the minimum runtime requirements, add below a pseudocode of your implementation for the optimal solution. It does not have to follow any specific syntax, it's pseudocode. (If it does meet the minimum requirements, ignore this question)
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