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Puedes explicar el procedimiento para este resultado? = n p x = 0 n ( n - 1 ) ! ( x - 1 )

Puedes explicar el procedimiento para este resultado?=npx=0n(n-1)!(x-1)!(n-1-x+1)!(p)x-1(1-p)nx=np(p+1-p)nx
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