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Pure S is burned in dry air. The flue gas has the following composition: 8.17 mole% SOz. 0.90% molar SOs, 11.57% molar 02 and 79.36%

Pure S is burned in dry air. The flue gas has the following composition: 8.17 mole% SOz. 0.90% molar SOs, 11.57% molar 02 and 79.36% molar N2. Calculate the percentage in excess of oxygen that has been used with respect to that necessary for the complete combustion to SO3.

The base of calculus is 100 mol.

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2S+3O2=2SO3S+O2=SO2

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