Q 1. (05.03 MC) The table of values for f'(x) describes the behavior of continuous function f. Which of the following is true? (1 point) x 0 1 2 3 4 f'( x) -1 0 2 05 Of is increasing on (1, 3) only because f'(x) > 0. Of is increasing on (1, 3) and (3, 4) because f'(x) > 0. Of is decreasing on (1, 3) and (3, 4) because f'(x) > 0. Of is decreasing on (1, 3) only because f'(x) > 0. W Q 2. (05.03 MC) Justify why the function with f' = 2cosx + 2cosxsinx is decreasing from _ to Sit (1 point) 2 Of' ( x ) > 0 for (# 2 ) Of' ( x ) 0 for x Of' ( x ) > 0 for * 3xQ 3. (05.03 MC) Use the graph of f' to determine which statement is true regarding the critical points of f. (1 point) Graph off ' ( f(2) is a maximum because f' > 0 for x 2. Of(-2) is a minimum because f' 0 for x > -2. Of(0) is a relative extrema because f' = 0. There are no relative extrema for f.Q 1. (05.04 MC) Find the absolute maximum of f(x) = \\4 -x2 on [-2, 2]. (1 point) O - 2 Oo O 1 O 2 Q 2. (05.04 MC) Given g(x) = 0.5x# + 4x, determine the x-value for the absolute minimum of the function g(x) on [-2, 3]. (1 point) O o O V3 O - 2 Q 3. (05.04 MC) Let g(x) = 3x2 - 3x. At what value of x on the interval [0, 2] does g have a possible absolute maximum? (1 point) O Ni - O O 1 O 2D D 4. (05'04MC) What is the global minimum of the function f(x)= |x 2| on [5, 5]? (1 point) ] 5(05'04MC) Determine the x-value where a possible global maximum for a function h occurs on the interval -4 s x s 2 when h(x) = x3 - 4x2. (1 point) 4. (05.03 MC) Given f'(X ) = x2 -8x (x-4)2' determine the x-value where a relative maximum exists for f(x). (1 point) O X = 8 O X = 4 O X = 2 O X = 0 5. (05.03 MC) Given f'(x) = -2x2 V4-X2 determine where f(x) is decreasing. (1 point) O ( -00, - V2 ) and ( 12, 0. ) O [-2, - V2) and (V2, 2] O ( - 2, 2 ) O ( -Vz. V2]