Q$24.$ Calculate the equilibrium constant $K$ at $25C$ for the reaction

$(R=8\mathrm{.}314J_{mo{l}^{\text{'}}}{K}^{-1})$ :

$AgC{l}^{(s)}longleftrightarrowA{g}^{+}(aq)+Cr(aq)$

Using standard tree energy of formation $(G^2{k}^{2}kJmo{l}^{-1})$: AgCl$(s)=-109\mathrm{.}7,$

$A{g}^{\text{'}}(sq)=77\mathrm{.}1$ and $Cr(aq)=*\mathrm{.}131\mathrm{.}2$

A$.1\mathrm{.}8{10}^{-10}$

B$.2\mathrm{.}5{10}^{12}$

C$.6\mathrm{.}3{10}^{12}$

D$.9\mathrm{.}4{10}^{21}$

E$.3\mathrm{.}5{10}^{17}$