Question: Q 5 . UDP and TCP use 1 s complement for their checksums. Suppose you have the following three 8 - bit bytes: (

Q5. UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: \(01010011,01100110,0110100\). What is the 1 s complement of the sum of these 8-bit bytes? (Note that although UDP and TCP use 16-bit words in computing the checksum, for this problem you are being asked to consider 8-bit sums.) Show all work. Why is it that UDP takes the 1 s complement of the sum; that is, why not just use the sum? With the 1s complement scheme, how does the receiver detect errors? Is it possible that a 1bit error will go undetected? How about a 2-bit error?
Q 5 . UDP and TCP use 1 s complement for their

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