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Q1 Q2 Q3 Suppose that the power series > ((x - 2) converges when z = 0 and diverges when z = 7. Q4 The

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Q1 Q2 Q3 Suppose that the power series > ((x - 2)" converges when z = 0 and diverges when z = 7. Q4 The smallest possible interval of convergence is Q5 The largest possible interval of convergence is. Select a blank to input an answer Q4 SAVE HELP O REPORT Consider the series ( 2-0 73 (X - 1)" . Fill in the blank to find the radius of convergence and interval of convergence. With a,, = = 735 ( X - 1)", we have lim lim = lim Thus by the ratio test the series converges when . Thus the radius of convergence is .Therefore the series converges when or equivalently We now test the end points of this interval. When z = the power series converges, by the alternating series test. When a =the power series diverges, since it's the harmonic series. Thus the interval of convergence is . Select a blank to input an answer Q5

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