Q3: As electric current moves through a wire, heat generated by resistance is conducted through a layer of insulation and then convected to the surrounding air. The steady-state temperature of the wire can be computed as Determine the thickness of insulation r1(m) that minimizes the wire's temperature given the following parameters: T=Tair+2q[k1ln(rwrw+ri)+h1rw+ri1] q= heat generation rate =75W/m,rw= wire radius =6mm,k= thermal conductivity of insulation =0.17W/(mK),h= convective heat transfer coefficient =12W/(m2K), and Tair= air temperature =293K