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q3 Part A An open container holds ice of mass 0.535 kg at a temperature of -13.0 C . The mass of the container can
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Part A An open container holds ice of mass 0.535 kg at a temperature of -13.0 "C . The mass of the container can be ignored. Heat is supplied to the How much time melts passes before the ice starts to melt? container at the constant rate of 850 J/minute View Available Hint(s) The specific heat of ice to is 2100 J/kg . K and the heat of fusion for ice is 334 x 10* J/kg. tmelts = 17.2 minutes Submit Previous Answers Correct Correct answer is shown. Your answer 17 minutes was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. Part B From the time when the heating begins, how much time trise does it take before the temperature begins to rise above 0" C? View Available Hint(s) JA AEd trise = 207.77 minutes Submit Previous Answers X Incorrect; Try Again; 9 attempts remaining This is the time needed from the time the temperature first reaches 0" C, not from the time since the heating is started. Provide Feedback Next >Giroon Ti = - 13 C bisEs . Q = lee 8. = 850 J /minutes Co = 2100 J / FgK f = 334 x 103 5/ kg solution Total hoat rocquised for ice to melting of ice at oc Tylee + ( 21 - 0 ) - hee = 8 = ( 2100X (0 - (- 13 ) ) + 334 x 10 - 0. 535X 2100*13 + 334 X10's = 193295 . 5 JHeat supply 20to = 8 xt = 8 ( No ( 088 ) 850xt = 193295.5 rise > trise = 193295. 5 850 - trig = 227- 406 minutes tong = 227.41 onlowtesStep by Step Solution
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